@tim_skold vs @bombon_sawa: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of SKOLD (@tim_skold) and 鈴木砂羽 (@bombon_sawa) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @tim_skold leads in 5 of 9 metrics.
@bombon_sawa has 107,999 Instagram followers — 51,749 more than @tim_skold (56,250).
@tim_skold

SKOLD

@tim_skold

@marilynmanson

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@bombon_sawa

鈴木砂羽

@bombon_sawa

更新頻度少なめ?GO⇨Nail専用instagramアカウント⇨ bom_nail ☆⇨ X⇨@bom_schedule ストーリーにはほぼ毎日いる😸MONDAY LLC🌕公式FC「さわにゃん組」→

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@tim_skold Metric @bombon_sawa
56.2K Followers 108.0K
16 Total Posts 997
12 Recent Posts Analyzed 12
11.9K Avg Likes / Post 2.7K
20 Avg Comments / Post 35
11.9K Avg Engagement / Post 2.7K
69.0K Best Post Likes 6.8K
21% Engagement Rate (%) 2%
3.5K Followers per Post 108
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

Frequently Asked Questions

Who has more Instagram followers, @tim_skold or @bombon_sawa?

@bombon_sawa has more Instagram followers than @tim_skold: 107,999 vs 56,250.

Which account has higher engagement, @tim_skold or @bombon_sawa?

@tim_skold has a higher Instagram engagement rate (21.13%) than @bombon_sawa (2.5%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

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