@jessicaspringsteen vs @alyshanewman: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of Jessica Springsteen (@jessicaspringsteen) and 🇨🇦Alysha Newman Oly🇨🇦 (@alyshanewman) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @alyshanewman leads in 7 of 9 metrics.
@alyshanewman has 712,858 Instagram followers — 289,125 more than @jessicaspringsteen (423,733).
@jessicaspringsteen

Jessica Springsteen

@jessicaspringsteen

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@alyshanewman

🇨🇦Alysha Newman Oly🇨🇦

@alyshanewman

Olympic Medalist | Record Holder First Canadian Olympic PV Medalist Founder @bolton_athletics Wellness•Fashion•Speaker RAISE THE BAR WHEREVER YOU GO

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@jessicaspringsteen Metric @alyshanewman
423.7K Followers 712.9K
1.0K Total Posts 641
12 Recent Posts Analyzed 12
18.9K Avg Likes / Post 232.6K
118 Avg Comments / Post 1.1K
19.1K Avg Engagement / Post 233.8K
28.6K Best Post Likes 2.6M
4% Engagement Rate (%) 32%
421 Followers per Post 1.1K
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

Frequently Asked Questions

Who has more Instagram followers, @jessicaspringsteen or @alyshanewman?

@alyshanewman has more Instagram followers than @jessicaspringsteen: 712,858 vs 423,733.

Which account has higher engagement, @jessicaspringsteen or @alyshanewman?

@alyshanewman has a higher Instagram engagement rate (32.79%) than @jessicaspringsteen (4.5%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

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