@greenfieldsings vs @di_borisova__: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of Jessica Greenfield (@greenfieldsings) and Diana Borisova (@di_borisova__) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @di_borisova__ leads in 5 of 9 metrics.
@di_borisova__ has 32,598 Instagram followers — 16,000 more than @greenfieldsings (16,598).
@greenfieldsings

Jessica Greenfield

@greenfieldsings

Singer/Songwriter in @wearewonder45 Member of @themightyi Noel Gallagher's High Flying Birds.

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@di_borisova__

Diana Borisova

@di_borisova__

Трёхкратная чемпионка мира и Европы по художественной гимнастике Заслуженный мастер спорта России @gymnasiumteam

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@greenfieldsings Metric @di_borisova__
16.6K Followers 32.6K
1.1K Total Posts 110
12 Recent Posts Analyzed 12
553 Avg Likes / Post 642
47 Avg Comments / Post 22
600 Avg Engagement / Post 664
3.3K Best Post Likes 3.5K
3% Engagement Rate (%) 2%
16 Followers per Post 296
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

Frequently Asked Questions

Who has more Instagram followers, @greenfieldsings or @di_borisova__?

@di_borisova__ has more Instagram followers than @greenfieldsings: 32,598 vs 16,598.

Which account has higher engagement, @greenfieldsings or @di_borisova__?

@greenfieldsings has a higher Instagram engagement rate (3.61%) than @di_borisova__ (2.04%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

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