@esthervalleeofficial vs @chrisporterofficial: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of Esther Vallee (@esthervalleeofficial) and Chris Porter (@chrisporterofficial) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @chrisporterofficial leads in 8 of 9 metrics.
@chrisporterofficial has 6,094 Instagram followers — 2,935 more than @esthervalleeofficial (3,159).
@esthervalleeofficial

Esther Vallee

@esthervalleeofficial

EP Time’s Up out now ❤️ video out on yt ☁️

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@chrisporterofficial

Chris Porter

@chrisporterofficial

See Instagram photos and videos from Chris Porter (@chrisporterofficial)

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@esthervalleeofficial Metric @chrisporterofficial
3.2K Followers 6.1K
135 Total Posts 223
12 Recent Posts Analyzed 12
87 Avg Likes / Post 792
9 Avg Comments / Post 21
96 Avg Engagement / Post 813
182 Best Post Likes 2.1K
3% Engagement Rate (%) 13%
23 Followers per Post 27
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

Frequently Asked Questions

Who has more Instagram followers, @esthervalleeofficial or @chrisporterofficial?

@chrisporterofficial has more Instagram followers than @esthervalleeofficial: 6,094 vs 3,159.

Which account has higher engagement, @esthervalleeofficial or @chrisporterofficial?

@chrisporterofficial has a higher Instagram engagement rate (13.34%) than @esthervalleeofficial (3.05%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

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