@dlalathukzin vs @flula: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of π•Έπ–†π–Œπ–Žπ–ˆ π•³π–†π–“π–‰π–Ÿ (@dlalathukzin) and Flula Borg (@flula) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @flula leads in 7 of 9 metrics.
@flula has 1,115,409 Instagram followers — 559,409 more than @dlalathukzin (556,000).
@dlalathukzin

π•Έπ–†π–Œπ–Žπ–ˆ π•³π–†π–“π–‰π–Ÿ

@dlalathukzin βœ“

See Instagram photos and videos from π•Έπ–†π–Œπ–Žπ–ˆ π•³π–†π–“π–‰π–Ÿ (@dlalathukzin)

View full stats page β†’
@flula

Flula Borg

@flula βœ“

Hallo!

View full stats page β†’
@dlalathukzin Metric @flula
556.0K Followers 1.1M
631 Total Posts 1.5K
12 Recent Posts Analyzed 12
15.7K Avg Likes / Post 70.7K
181 Avg Comments / Post 635
15.9K Avg Engagement / Post 71.4K
86.6K Best Post Likes 374.4K
2% Engagement Rate (%) 6%
881 Followers per Post 744
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post Γ— 100.

Frequently Asked Questions

Who has more Instagram followers, @dlalathukzin or @flula?

@flula has more Instagram followers than @dlalathukzin: 1,115,409 vs 556,000.

Which account has higher engagement, @dlalathukzin or @flula?

@flula has a higher Instagram engagement rate (6.4%) than @dlalathukzin (2.86%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post Γ— 100.

Compare these creators to others

@dlalathukzin vs

Or browse more featured creator comparisons β†’