@diachenko29 vs @kaleyn2020: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of Olena Diachenko πŸ‘€ (@diachenko29) and Boryana KaleynπŸ’› (@kaleyn2020) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @kaleyn2020 leads in 7 of 9 metrics.
@kaleyn2020 has 63,928 Instagram followers — 27,922 more than @diachenko29 (36,006).
@diachenko29

Olena Diachenko πŸ‘€

@diachenko29

Coach & Gymnast UKR & CHN Team πŸ‡ΊπŸ‡¦πŸ‡¨πŸ‡³ 2019 World Universiade πŸ₯ˆπŸ₯ˆπŸ₯ˆ For cooperation Direct πŸ“©

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@kaleyn2020

Boryana KaleynπŸ’›

@kaleyn2020

Olympic Games Paris 2024 -πŸ₯ˆ Olympic Games Tokyo 2020 - 5th place World Championships - x1πŸ₯‡Ρ…3πŸ₯ˆ European Championships -Ρ…7πŸ₯‡Ρ…3πŸ₯ˆΡ…7πŸ₯‰

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@diachenko29 Metric @kaleyn2020
36.0K Followers 63.9K
1.1K Total Posts 363
12 Recent Posts Analyzed 12
2.1K Avg Likes / Post 5.3K
48 Avg Comments / Post 60
2.2K Avg Engagement / Post 5.4K
8.0K Best Post Likes 21.4K
6% Engagement Rate (%) 8%
33 Followers per Post 176
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post Γ— 100.

Frequently Asked Questions

Who has more Instagram followers, @diachenko29 or @kaleyn2020?

@kaleyn2020 has more Instagram followers than @diachenko29: 63,928 vs 36,006.

Which account has higher engagement, @diachenko29 or @kaleyn2020?

@kaleyn2020 has a higher Instagram engagement rate (8.38%) than @diachenko29 (6.01%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post Γ— 100.

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