@alina.walbrun vs @jeffkoons: Instagram Profiles Compared

A side-by-side comparison of the Instagram profiles of Alina 👩🏼‍⚕️ (@alina.walbrun) and Jeff Koons (@jeffkoons) across 9 metrics — followers, engagement rate, average likes, best post, and more. Data is from IGDataHub's continuous data collection.

Verdict: @alina.walbrun leads in 5 of 9 metrics.
@jeffkoons has 542,420 Instagram followers — 261,179 more than @alina.walbrun (281,241).
@alina.walbrun

Alina 👩🏼‍⚕️

@alina.walbrun

👩🏼‍⚕️ Abgeschlossenes Medizinstudium 🧠 Aktuell Psychologie in Harvard (Extension School)

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@jeffkoons

Jeff Koons

@jeffkoons

See Instagram photos and videos from Jeff Koons (@jeffkoons)

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@alina.walbrun Metric @jeffkoons
281.2K Followers 542.4K
445 Total Posts 314
12 Recent Posts Analyzed 12
22.4K Avg Likes / Post 5.3K
57 Avg Comments / Post 111
22.4K Avg Engagement / Post 5.4K
96.4K Best Post Likes 23.1K
7% Engagement Rate (%) 0%
632 Followers per Post 1.7K
Methodology: Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

Frequently Asked Questions

Who has more Instagram followers, @alina.walbrun or @jeffkoons?

@jeffkoons has more Instagram followers than @alina.walbrun: 542,420 vs 281,241.

Which account has higher engagement, @alina.walbrun or @jeffkoons?

@alina.walbrun has a higher Instagram engagement rate (7.97%) than @jeffkoons (0.99%).

How is this comparison calculated?

Follower count, post count, and verification status come directly from each Instagram profile. Engagement metrics (likes, comments, engagement rate) are computed from a sample of each account's most recent posts captured by IGDataHub. Engagement rate = (likes + comments) / followers per post × 100.

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